Mr. Steven van der Sluis 0 Report post Posted December 12, 2019 Hello, I have a few (beginners) problems. I have been making the tutorial of the fast monohull vessel. And in the process adding some of my own modifications. However I have a strange situation, though it does not cause a real problem. I have defined the FOS, with forward intermediate point at x=60. When I create a metasurface, that extends from somewhere aft, to this x=60, Caeses actually creates it up to 59.908. Is this the way it should be? (the attached screenshots describe this problem) Another thing, but this does cause a problem is that I am not able to extract a t value as start of the domain for creating an imagesurface (called srf_mid_trimmed). I created an image curve called CL_midsurface, which is the original length of the midsurface. And I try to get a t value using CL_midsurface.ft(0,x position of the start of the domain). But this does not give me the correct start of the imagesurface. I hope someone can help me with this.hull2.fdbc Share this post Link to post Share on other sites
Ceyhan Erdem 14 Report post Posted December 16, 2019 Hi Steven, Please check the attached project.I have observed that, your function curve which is supposed to provide the x-position is not defined correctly. What the curve engine does is from the abcissa value (depending on your coordinate system) obtain the ordinate and provide this value as an input. I have created a new function curve and got rid of the scale parameter. Coming to your second question, when I use the command; CL_midsurface.ft(0,20) ; I assume 20 is the starting x-position I obtain the correct value for position parameter which is 0. CheersCeyhanhull2.fdbc Share this post Link to post Share on other sites
Mr. Steven van der Sluis 0 Report post Posted December 17, 2019 Hi Ceyhan, Thank you for looking into this. Regarding this scale, I feel kinda stupid. I had forgotten that problem already and the quick and dirty solution I used. Regarding the second problem. I think I did not explain so clearly. It is not CL_midsurface.ft(0,20) I want to use. I need the t value for for a certain x position. This x position is the intersection of the top of the skeg with the FOB. Which should be at 22.5364. If I do CL_midsurface.ft(0,22.5364) I get a t of 0.0614. If I use this t-value in de srf_mid_trimmed domain, there is an overlap with the skeg. If I then determine the x of this srf_mid_trimmed, it is not at 22.5364 but at 22.4529. This x value on the CL_midsurface corresponds to a 0.05938 and not the previously determined and manually given as domain boundardy of 0.0614. I have made an extra scope called "secondproblem" in which the info concerned is grouped. grtz, Steven *EDIT*renamed the srf_mid_trimmed surface in my post, to avoid confusion and attached the proper hull3.fdbchull3.fdbc Share this post Link to post Share on other sites
Mr. Steven van der Sluis 0 Report post Posted December 17, 2019 Found it! The forward boundary was not in the intended X position, messing up my t value in the aft. Sorry for the bother. Share this post Link to post Share on other sites
Ceyhan Erdem 14 Report post Posted December 19, 2019 Hi Steven, Good to hear that you have resolved it.Please let me know if you have further questions. CheersCeyhan Share this post Link to post Share on other sites