Gustaf Magnander 0 Report post Posted November 10, 2023 Dear forum members, Is there an easy way to find the normalized value, that represent a certain real z-value, that I can use for the "Tp-value" when using the point type "position on curve"? Thanks, //Gustaf Share this post Link to post Share on other sites
Mr. Heinrich von Zadow 9 Report post Posted November 10, 2023 Hi Gustav, you could create a point through the console with: point p(curve.fv(2,zVal)) Instead of "curve" you'll have to choose your particular curve and zVal would be your z value. "2" corresponds to the z-axis (0=x, 1=y, 2=z). Share this post Link to post Share on other sites
Mr. Heinrich von Zadow 9 Report post Posted November 10, 2023 ... if you use .ft instead of .fv you'd get the t-value instead... Share this post Link to post Share on other sites
Gustaf Magnander 0 Report post Posted November 10, 2023 49 minutes ago, Mr. Heinrich von Zadow said: Hi Gustav, you could create a point through the console with: point p(curve.fv(2,zVal)) Instead of "curve" you'll have to choose your particular curve and zVal would be your z value. "2" corresponds to the z-axis (0=x, 1=y, 2=z). Thank you Heinrich, I will try this and also the ft alternative that you suggested //Gustaf Share this post Link to post Share on other sites
Gustaf Magnander 0 Report post Posted November 10, 2023 Hi again Heinrich, I tested what you suggested and the points were created, but the position was wrong. I attach an image so it becomes easier to explain what I want to do. The point I have marked "1" is the point which has the z-value I want to use. The red cross marks the approximate position on the curve where I want the new point to be. The point in the bow which I have marked with "2" is where the point actually is positioned after creating the point with: point p(curve.fv(2,zVal)). I also tested the command: point p(curve.ft(2, zVal)) but then the point was positioned really far aft (not visible on the screenshot). I hope this helps to describe my problem. Thanks again! //Gustaf Share this post Link to post Share on other sites
Gustaf Magnander 0 Report post Posted November 10, 2023 1 minute ago, Gustaf Magnander said: Hi again Heinrich, I tested what you suggested and the points were created, but the position was wrong. I attach an image so it becomes easier to explain what I want to do. The point I have marked "1" is the point which has the z-value I want to use. The red cross marks the approximate position on the curve where I want the new point to be. The point in the bow which I have marked with "2" is where the point actually is positioned after creating the point with: point p(curve.fv(2,zVal)). I also tested the command: point p(curve.ft(2, zVal)) but then the point was positioned really far aft (not visible on the screenshot). I hope this helps to describe my problem. Thanks again! //Gustaf I could also say that the b-spline in the center works as a control curve and controls the outer generic curve in the z-direction. The point on the b-spline which is marked with "1" thus also has the correct x-value. I control the generic outer curve in the xy-plane with a multisegmented curve (not visible in the screenshot). Share this post Link to post Share on other sites
Mr. Heinrich von Zadow 9 Report post Posted November 10, 2023 Hi Gustav, in your case you would have to us p2:z as elevation for the fv command: point p1(curve.fv(2,p2:z)) let me know if this explains it -- otherwise feel free to attach your particular example and I'll quickly modify it. Cheers, Heinrich Share this post Link to post Share on other sites
Gustaf Magnander 0 Report post Posted November 10, 2023 6 minutes ago, Mr. Heinrich von Zadow said: Hi Gustav, in your case you would have to us p2:z as elevation for the fv command: point p1(curve.fv(2,p2:z)) let me know if this explains it -- otherwise feel free to attach your particular example and I'll quickly modify it. Cheers, Heinrich Hi Heinrich, I actually use :z to get the z-value, see attached screenshot. planing_hull_v03.cdb Share this post Link to post Share on other sites
Mr. Heinrich von Zadow 9 Report post Posted November 10, 2023 Hi Gustav, well, that's the x-value 😉 See attached project... Cheers, Heinrich planing_hull_v03.cdb Share this post Link to post Share on other sites
Gustaf Magnander 0 Report post Posted November 10, 2023 48 minutes ago, Mr. Heinrich von Zadow said: Hi Gustav, well, that's the x-value 😉 See attached project... Cheers, Heinrich planing_hull_v03.cdb 932 kB · 0 downloads Yea, it was, 🙂 Thank you Heinrich! Share this post Link to post Share on other sites
Gustaf Magnander 0 Report post Posted November 10, 2023 12 minutes ago, Gustaf Magnander said: Yea, it was, 🙂 Thank you Heinrich! actually Heinrich, The x-value of the maxZ point was set as a discrete value. I want to automaticly retrieve this x-value based on the maxZ point, which change position if I vary the shape of the "knuckleRaiseCurve" Thus, if I vary the shape of the "knuckleRaiseCurve" in the xz-plane the point maxZ automatically get the max z-value, but I want to automatically also retreive the correspoinding x-value, when maxZ position changes. Share this post Link to post Share on other sites
Mr. Heinrich von Zadow 9 Report post Posted November 10, 2023 Hi Gustaf (sorry for misspelling your name repeatedly!), with .getmax(2,true) you can return the max value along the z-axis of a curve (the "true" will return the parameter position of that max value, instead of the value itself). This parameter can now be used again, to acces the position of the curve at that parameter with .getPos() This should be what you need -- see attached project again for your specific example. planing_hull_v03.cdb Share this post Link to post Share on other sites
Gustaf Magnander 0 Report post Posted November 10, 2023 1 hour ago, Mr. Heinrich von Zadow said: Hi Gustaf (sorry for misspelling your name repeatedly!), with .getmax(2,true) you can return the max value along the z-axis of a curve (the "true" will return the parameter position of that max value, instead of the value itself). This parameter can now be used again, to acces the position of the curve at that parameter with .getPos() This should be what you need -- see attached project again for your specific example. planing_hull_v03.cdb 932 kB · 0 downloads Hi Heinrich, No worries! Thank you, yes, I wanted to have the parameter position corresponding to the max z value. I will have a look in the project you fixed. Thanks again! //Gustaf Share this post Link to post Share on other sites